On a DL1, is the 5V out circuit protected internally for excessive current draw? Or should I use an inline fuse prior to all my sensors to protect the DL1?
Thanks.
5V out current protected?
I can't give you an electrical engineer's answer, because I'm mechanical.
Nevertheless, I think I can safely say that the answers are
Yes, and
No.
I have not "blown" very fine sensors (pt100 RTD), or the DL1 with a short between 5V and an AV input, which I have probably inadvertantly arranged.
I don't think I've actually connected the 5V to ground, but as the specs state it's 100 mA max current draw, I'm interpreting that to mean it will not supply more than this but is happy pumping it out all day long.
Support confirmation please
Nevertheless, I think I can safely say that the answers are
Yes, and
No.
I have not "blown" very fine sensors (pt100 RTD), or the DL1 with a short between 5V and an AV input, which I have probably inadvertantly arranged.
I don't think I've actually connected the 5V to ground, but as the specs state it's 100 mA max current draw, I'm interpreting that to mean it will not supply more than this but is happy pumping it out all day long.
Support confirmation please
Understand fully.
That's why I mentioned that I don't think I've "connected" (shorted) to ground myself.
It would be nice to now.
By the way, we've all but written off the "same" car twice, without damaging the DL1.
The best involved multiple barrel rolls...
But... I've had two units fail in a go kart.
That's why I mentioned that I don't think I've "connected" (shorted) to ground myself.
It would be nice to now.
By the way, we've all but written off the "same" car twice, without damaging the DL1.
The best involved multiple barrel rolls...
But... I've had two units fail in a go kart.
There is some internal protection on the voltage regulator, in that it will turn itself off if the internal temperature gets too high. In theory this will protect it against short circuits to ground. What it is not protected against is putting volts in on that pin. So if you connect the 5v output to 12v you are likely to blow it up...
Martin
Martin
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